All numbers are equal
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Poza publicata in [ Math ]
Theorem: All numbers are equal.
Proof: Choose arbitrary a and b, and let t = a + b. Then
a + b = t
(a + b)(a – b) = t(a – b)
a^2 – b^2 = ta – tb
a^2 – ta = b^2 – tb
a^2 – ta + (t^2)/4 = b^2 – tb + (t^2)/4
(a – t/2)^2 = (b – t/2)^2
a – t/2 = b – t/2
a = b
So all numbers are the same, and math is pointless.
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